3.2102 \(\int \frac {(3+5 x)^3}{(1-2 x)^{3/2} (2+3 x)^4} \, dx\)

Optimal. Leaf size=100 \[ \frac {11 (5 x+3)^2}{7 \sqrt {1-2 x} (3 x+2)^3}+\frac {2 \sqrt {1-2 x} (470 x+297)}{441 (3 x+2)^3}-\frac {4660 \sqrt {1-2 x}}{3087 (3 x+2)}-\frac {9320 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{3087 \sqrt {21}} \]

[Out]

-9320/64827*arctanh(1/7*21^(1/2)*(1-2*x)^(1/2))*21^(1/2)+11/7*(3+5*x)^2/(2+3*x)^3/(1-2*x)^(1/2)-4660/3087*(1-2
*x)^(1/2)/(2+3*x)+2/441*(297+470*x)*(1-2*x)^(1/2)/(2+3*x)^3

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Rubi [A]  time = 0.03, antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {98, 145, 51, 63, 206} \[ \frac {11 (5 x+3)^2}{7 \sqrt {1-2 x} (3 x+2)^3}+\frac {2 \sqrt {1-2 x} (470 x+297)}{441 (3 x+2)^3}-\frac {4660 \sqrt {1-2 x}}{3087 (3 x+2)}-\frac {9320 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{3087 \sqrt {21}} \]

Antiderivative was successfully verified.

[In]

Int[(3 + 5*x)^3/((1 - 2*x)^(3/2)*(2 + 3*x)^4),x]

[Out]

(-4660*Sqrt[1 - 2*x])/(3087*(2 + 3*x)) + (11*(3 + 5*x)^2)/(7*Sqrt[1 - 2*x]*(2 + 3*x)^3) + (2*Sqrt[1 - 2*x]*(29
7 + 470*x))/(441*(2 + 3*x)^3) - (9320*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(3087*Sqrt[21])

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 98

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c -
a*d)*(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^(p + 1))/(b*(b*e - a*f)*(m + 1)), x] + Dist[1/(b*(b*e - a*
f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 2)*(e + f*x)^p*Simp[a*d*(d*e*(n - 1) + c*f*(p + 1)) + b*c*(d
*e*(m - n + 2) - c*f*(m + p + 2)) + d*(a*d*f*(n + p) + b*(d*e*(m + 1) - c*f*(m + n + p + 1)))*x, x], x], x] /;
FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && GtQ[n, 1] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p
] || IntegersQ[p, m + n])

Rule 145

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol] :
> Simp[((b^3*c*e*g*(m + 2) - a^3*d*f*h*(n + 2) - a^2*b*(c*f*h*m - d*(f*g + e*h)*(m + n + 3)) - a*b^2*(c*(f*g +
e*h) + d*e*g*(2*m + n + 4)) + b*(a^2*d*f*h*(m - n) - a*b*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(n + 1)) + b^2*(c*(
f*g + e*h)*(m + 1) - d*e*g*(m + n + 2)))*x)*(a + b*x)^(m + 1)*(c + d*x)^(n + 1))/(b^2*(b*c - a*d)^2*(m + 1)*(m
+ 2)), x] + Dist[(f*h)/b^2 - (d*(m + n + 3)*(a^2*d*f*h*(m - n) - a*b*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(n + 1)
) + b^2*(c*(f*g + e*h)*(m + 1) - d*e*g*(m + n + 2))))/(b^2*(b*c - a*d)^2*(m + 1)*(m + 2)), Int[(a + b*x)^(m +
2)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && (LtQ[m, -2] || (EqQ[m + n + 3, 0] &&  !L
tQ[n, -2]))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(3+5 x)^3}{(1-2 x)^{3/2} (2+3 x)^4} \, dx &=\frac {11 (3+5 x)^2}{7 \sqrt {1-2 x} (2+3 x)^3}-\frac {1}{7} \int \frac {(-74-160 x) (3+5 x)}{\sqrt {1-2 x} (2+3 x)^4} \, dx\\ &=\frac {11 (3+5 x)^2}{7 \sqrt {1-2 x} (2+3 x)^3}+\frac {2 \sqrt {1-2 x} (297+470 x)}{441 (2+3 x)^3}+\frac {4660}{441} \int \frac {1}{\sqrt {1-2 x} (2+3 x)^2} \, dx\\ &=-\frac {4660 \sqrt {1-2 x}}{3087 (2+3 x)}+\frac {11 (3+5 x)^2}{7 \sqrt {1-2 x} (2+3 x)^3}+\frac {2 \sqrt {1-2 x} (297+470 x)}{441 (2+3 x)^3}+\frac {4660 \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx}{3087}\\ &=-\frac {4660 \sqrt {1-2 x}}{3087 (2+3 x)}+\frac {11 (3+5 x)^2}{7 \sqrt {1-2 x} (2+3 x)^3}+\frac {2 \sqrt {1-2 x} (297+470 x)}{441 (2+3 x)^3}-\frac {4660 \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )}{3087}\\ &=-\frac {4660 \sqrt {1-2 x}}{3087 (2+3 x)}+\frac {11 (3+5 x)^2}{7 \sqrt {1-2 x} (2+3 x)^3}+\frac {2 \sqrt {1-2 x} (297+470 x)}{441 (2+3 x)^3}-\frac {9320 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{3087 \sqrt {21}}\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 59, normalized size = 0.59 \[ \frac {18640 (3 x+2)^3 \, _2F_1\left (-\frac {1}{2},2;\frac {1}{2};\frac {3}{7}-\frac {6 x}{7}\right )+49 \left (7875 x^2+10434 x+3457\right )}{27783 \sqrt {1-2 x} (3 x+2)^3} \]

Antiderivative was successfully verified.

[In]

Integrate[(3 + 5*x)^3/((1 - 2*x)^(3/2)*(2 + 3*x)^4),x]

[Out]

(49*(3457 + 10434*x + 7875*x^2) + 18640*(2 + 3*x)^3*Hypergeometric2F1[-1/2, 2, 1/2, 3/7 - (6*x)/7])/(27783*Sqr
t[1 - 2*x]*(2 + 3*x)^3)

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fricas [A]  time = 0.95, size = 99, normalized size = 0.99 \[ \frac {4660 \, \sqrt {21} {\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )} \log \left (\frac {3 \, x + \sqrt {21} \sqrt {-2 \, x + 1} - 5}{3 \, x + 2}\right ) - 21 \, {\left (83880 \, x^{3} + 178015 \, x^{2} + 125154 \, x + 29177\right )} \sqrt {-2 \, x + 1}}{64827 \, {\left (54 \, x^{4} + 81 \, x^{3} + 18 \, x^{2} - 20 \, x - 8\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^3/(1-2*x)^(3/2)/(2+3*x)^4,x, algorithm="fricas")

[Out]

1/64827*(4660*sqrt(21)*(54*x^4 + 81*x^3 + 18*x^2 - 20*x - 8)*log((3*x + sqrt(21)*sqrt(-2*x + 1) - 5)/(3*x + 2)
) - 21*(83880*x^3 + 178015*x^2 + 125154*x + 29177)*sqrt(-2*x + 1))/(54*x^4 + 81*x^3 + 18*x^2 - 20*x - 8)

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giac [A]  time = 1.27, size = 93, normalized size = 0.93 \[ \frac {4660}{64827} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {2662}{2401 \, \sqrt {-2 \, x + 1}} + \frac {29853 \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} - 137186 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 157633 \, \sqrt {-2 \, x + 1}}{86436 \, {\left (3 \, x + 2\right )}^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^3/(1-2*x)^(3/2)/(2+3*x)^4,x, algorithm="giac")

[Out]

4660/64827*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 2662/2401/sqr
t(-2*x + 1) + 1/86436*(29853*(2*x - 1)^2*sqrt(-2*x + 1) - 137186*(-2*x + 1)^(3/2) + 157633*sqrt(-2*x + 1))/(3*
x + 2)^3

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maple [A]  time = 0.02, size = 66, normalized size = 0.66 \[ -\frac {9320 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{64827}+\frac {2662}{2401 \sqrt {-2 x +1}}+\frac {-\frac {6634 \left (-2 x +1\right )^{\frac {5}{2}}}{2401}+\frac {39196 \left (-2 x +1\right )^{\frac {3}{2}}}{3087}-\frac {6434 \sqrt {-2 x +1}}{441}}{\left (-6 x -4\right )^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x+3)^3/(-2*x+1)^(3/2)/(3*x+2)^4,x)

[Out]

2662/2401/(-2*x+1)^(1/2)+54/2401*(-3317/27*(-2*x+1)^(5/2)+137186/243*(-2*x+1)^(3/2)-157633/243*(-2*x+1)^(1/2))
/(-6*x-4)^3-9320/64827*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.46, size = 101, normalized size = 1.01 \[ \frac {4660}{64827} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) - \frac {2 \, {\left (41940 \, {\left (2 \, x - 1\right )}^{3} + 303835 \, {\left (2 \, x - 1\right )}^{2} + 1464316 \, x - 145187\right )}}{3087 \, {\left (27 \, {\left (-2 \, x + 1\right )}^{\frac {7}{2}} - 189 \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} + 441 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 343 \, \sqrt {-2 \, x + 1}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)^3/(1-2*x)^(3/2)/(2+3*x)^4,x, algorithm="maxima")

[Out]

4660/64827*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) - 2/3087*(41940*(2*x - 1
)^3 + 303835*(2*x - 1)^2 + 1464316*x - 145187)/(27*(-2*x + 1)^(7/2) - 189*(-2*x + 1)^(5/2) + 441*(-2*x + 1)^(3
/2) - 343*sqrt(-2*x + 1))

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mupad [B]  time = 1.24, size = 82, normalized size = 0.82 \[ \frac {\frac {59768\,x}{1701}+\frac {86810\,{\left (2\,x-1\right )}^2}{11907}+\frac {9320\,{\left (2\,x-1\right )}^3}{9261}-\frac {5926}{1701}}{\frac {343\,\sqrt {1-2\,x}}{27}-\frac {49\,{\left (1-2\,x\right )}^{3/2}}{3}+7\,{\left (1-2\,x\right )}^{5/2}-{\left (1-2\,x\right )}^{7/2}}-\frac {9320\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{64827} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5*x + 3)^3/((1 - 2*x)^(3/2)*(3*x + 2)^4),x)

[Out]

((59768*x)/1701 + (86810*(2*x - 1)^2)/11907 + (9320*(2*x - 1)^3)/9261 - 5926/1701)/((343*(1 - 2*x)^(1/2))/27 -
(49*(1 - 2*x)^(3/2))/3 + 7*(1 - 2*x)^(5/2) - (1 - 2*x)^(7/2)) - (9320*21^(1/2)*atanh((21^(1/2)*(1 - 2*x)^(1/2
))/7))/64827

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3+5*x)**3/(1-2*x)**(3/2)/(2+3*x)**4,x)

[Out]

Timed out

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